Tuesday, May 6, 2008

Monday, April 28, 2008

Sarah

Sarah

altitude=

frequency=

period=

up or down=

add or subtract


altitude=5

frequency=12.4

period=2pi/12.4

up or down=upside down because it starts at zero so negative in front

add or subtract= add 5

Sunday, April 27, 2008

LINK

Tuesday, April 22, 2008

Assymptotes

Monday, April 7, 2008

-(x-2) (x-1) (x+3)


Christina

Sunday, April 6, 2008

Christian

Fatimah

Thursday, March 27, 2008

Good Luck Sarah

You can do it!

Wednesday, March 26, 2008

Sarah Word Problem


Make the equation (I am not sure if I rember all the detales exactly for this one , I am also not sure if it starts at zero , so if u can show mw what wouldt be the differance if it starts at zero or not)
A water flow reaches a min of 20 m and a max of 30 m , it takes it 6.2 hours to complete a full cycle it starts when t=0. write a sine and a cosine function to model the wave.
b) how long does it take to reach 28 m?





Range 30-20 is 10 so the amplitude is 5

Period is 6.2

Frequency is 2pi/6.2

Beginning point (0, 25)

y=____sin(____x+____)+____

y=5 sin(2pi/6.2 x ) +25

y=5 cos(2pi/6.2 x - pi/2) +25

To make it cos you need a phase shift of right of pi/2 (this is always true to go between sin and cos it doesn't matter what the numbers are)

To reach 28 m

Plug in 28 for y

28 =
y=5 sin(2pi/6.2 x ) +25

subtract 25

3 =
5 sin(2pi/6.2 x )

divide by 5

0.6 =
sin(2pi/6.2 x )

sin inverse of (0.6) =
2pi/6.2 x

.64 =
2pi/6.2 x

x = .63

So a little over half an hour.

YOU CAN SEE THIS ON THE GRAPH ABOVE

The final problem that I remember is
A wheel has a diameter of 70 and it is spins at 30 km/h
what is the angular velocity in m/s?



Sarah Graphing



-3 cos (x-pi/4)

Amplitude -3 so it is flipped upside down and 3 tall

then phase shift pi/4 to the right


4 sin(pi/2*x-pi/2)-1

Notice this has a phase shift of -pi/2 so it moves right

Frequency is pi/2 so the period is
2 pi divided by pi/2 (6.28/1.57)

Frequency is 4.

If you look at the graph you can see that one cycle completes at 4.


Prove the identites:
2tanx/1+tan squaredx=sin2x

2tanx/sec^2 x

2 tanx * cos^2 x

2 (sinx/cosx) *cos^2 x

2 sinx * cosx

sin2x


Cotx+tanx=2csc2x

cosx/sinx + sinx/cosx

cosxcosx/sinxcosx + sinxsinx/sinx
cosx

(cos^2 x +sin^2 x)/(sinxcosx)

1/sinxcosx (since 2sinxcosx= sin2x then sinxcosx = (1/2) sin(2x) )

2/sin(2x)

2csc(2x)


Solve for x
sin squaredx - cos squaredx=1/2

-cos^2 x + sin^2 x = 1/2 Use double angle formula

2cos^2 x-1= -1/2

2cos^2 x= 1/2

cos^2 x = 1/4

cos x = +or- 1/2

x = 2.09 or 1.05



2 sin squaredx - 3 cos squaredx=3