Thursday, March 27, 2008

Good Luck Sarah

You can do it!

Wednesday, March 26, 2008

Sarah Word Problem


Make the equation (I am not sure if I rember all the detales exactly for this one , I am also not sure if it starts at zero , so if u can show mw what wouldt be the differance if it starts at zero or not)
A water flow reaches a min of 20 m and a max of 30 m , it takes it 6.2 hours to complete a full cycle it starts when t=0. write a sine and a cosine function to model the wave.
b) how long does it take to reach 28 m?





Range 30-20 is 10 so the amplitude is 5

Period is 6.2

Frequency is 2pi/6.2

Beginning point (0, 25)

y=____sin(____x+____)+____

y=5 sin(2pi/6.2 x ) +25

y=5 cos(2pi/6.2 x - pi/2) +25

To make it cos you need a phase shift of right of pi/2 (this is always true to go between sin and cos it doesn't matter what the numbers are)

To reach 28 m

Plug in 28 for y

28 =
y=5 sin(2pi/6.2 x ) +25

subtract 25

3 =
5 sin(2pi/6.2 x )

divide by 5

0.6 =
sin(2pi/6.2 x )

sin inverse of (0.6) =
2pi/6.2 x

.64 =
2pi/6.2 x

x = .63

So a little over half an hour.

YOU CAN SEE THIS ON THE GRAPH ABOVE

The final problem that I remember is
A wheel has a diameter of 70 and it is spins at 30 km/h
what is the angular velocity in m/s?



Sarah Graphing



-3 cos (x-pi/4)

Amplitude -3 so it is flipped upside down and 3 tall

then phase shift pi/4 to the right


4 sin(pi/2*x-pi/2)-1

Notice this has a phase shift of -pi/2 so it moves right

Frequency is pi/2 so the period is
2 pi divided by pi/2 (6.28/1.57)

Frequency is 4.

If you look at the graph you can see that one cycle completes at 4.


Prove the identites:
2tanx/1+tan squaredx=sin2x

2tanx/sec^2 x

2 tanx * cos^2 x

2 (sinx/cosx) *cos^2 x

2 sinx * cosx

sin2x


Cotx+tanx=2csc2x

cosx/sinx + sinx/cosx

cosxcosx/sinxcosx + sinxsinx/sinx
cosx

(cos^2 x +sin^2 x)/(sinxcosx)

1/sinxcosx (since 2sinxcosx= sin2x then sinxcosx = (1/2) sin(2x) )

2/sin(2x)

2csc(2x)


Solve for x
sin squaredx - cos squaredx=1/2

-cos^2 x + sin^2 x = 1/2 Use double angle formula

2cos^2 x-1= -1/2

2cos^2 x= 1/2

cos^2 x = 1/4

cos x = +or- 1/2

x = 2.09 or 1.05



2 sin squaredx - 3 cos squaredx=3

Sarah Word Problem




She also asked to sate the amplitude , frequency , period , domain , range , phase shift , and reflection
Word problem:
The average monthly temperature of a town can be modelled by the function T(t)= 14.6 sin 0.5( t-1)+9.15. where T is the tempertaure in degrees and t=0 represents january first, t= 1 represents febrauary 1 etc...lkd
a) which month is the average monthly temperature the highest?the lowest?
b) use the model to predict when temp is 0?
c) when is the temperature 20?

T(t)= 14.6 sin 0.5( t-1)+9.15

amp=14.6
freq=.5
Phase shift= .5*-1 = -.5
Period=2pi/.5=4pi or approx 12
Domain= Infinity the sin graph goes on forever on the x-axis
Range= 9.15 then add 14.6 and get a maximum of 23.75 and then 9.15-14.6 and you get minimum of -5.45
reflection= ?


Since you are being asked the month with the maximum temp. You need to say

23.75=14.6 sin 0.5( t-1)+9.15

then you solve for t

subtract 9.15


14.6 =14.6 sin 0.5( t-1)

divide by 14.6

1= sin 0.5(t-1)

sin inverse of 1 = 0.5(t-1)

1.57 = 0.5(t-1)

3.14 = t-1

t=4.14

The maximum temperature is in May as May is equal to 4


When is the temperature 20 or 0

20=
14.6 sin 0.5( t-1)+9.15

t= 2.67 or Middle of March

0=
14.6 sin 0.5( t-1)+9.15

Solve them the same way as I showed above.




Monday, March 24, 2008

y=-sin(2x)+3

y=3cos(x+pi)

Remember the order for graphing sine and cosine

1st Amplitude
2nd Move up or down
3rd Frequency
4th Phase shift

y=sin(2x)+3

move it up 3
frequency is 2

y=-2cosx-3

Flip for the negative
Multiply by 2 for amplitude
Subtract 3

Rational equations



Sunday, March 23, 2008

Trig Identities




Multiply (2x+1)(x-1)

Find sin, tan....



Synthetic Division Alternative



Simplify Radicals

Integral



Saturday, March 22, 2008

Solve the system

Quadratic equation

Acceleration Graph

Graphing

Synthetic Divsion

Quadratic Solving Methods

Friday, March 21, 2008

Log Equations

Integration by Parts

Area between curves

Thursday, March 20, 2008

em hu



Graphing Linear Equations

Parabola in Standard Form

ihavaqst

Sylvia

Factoring Help

Algebra 2

Galbert

Radicals

mo4

Systems

Andrew

Wednesday, March 19, 2008

Cube-Johnny

Doggy

Adding Rationals-Justin

Rationals



The Integral

Tuesday, March 18, 2008